10 raiders kill a raid boss. Some of those raiders will use a bonus roll, and of those that use a bonus roll some will also win an item from it. In how many different ways can this happen?
This is harder than I thought.
Do you consider the raiders different people or not? If raider 1 takes a bonus roll and nobody else does, is this the same as raider 2 doing it and nobody else?
Last edited by reckoner04; 2013-02-13 at 03:49 PM.
There are 10 raiders, and each has 3 possibilities (no charm, charm with no loot, charm and loot).
3^10 = 59049
Naw, because the question simply asks how many different ways are possible. For example, let D = person doesn't use bonus roll, B = person uses bonus roll but doesn't win an item, I = person uses bonus roll and wins an item.
Then for 10 people one possibility is:
yet another is:
and so on...
This should make the problem a lot easier to understand/solve!
*edit* Static Transit got it correct before I posted this tip!
If you used a bonus roll, either you won it or not. Those are the two possibilities. The probability of winning an item doesn't change the fact that there are two possibilities.
Also, the concept of "almost" winning in a pass/fail roll system is an illusion. The pRNG system doesn't work like one of those hammer games at the carnival, where if you just put in a little extra effort you would've won.
In this hypothetical scenario, since each raider is an individual, I suppose we'd consider the order unique - and so, 4^10 is accurate.
LPing For The Future: http://www.youtube.com/user/MrSayier
I suppose I could rewrite it to:
10 raiders kill a raid boss. Some of those raiders will use a bonus roll. Of those that use a bonus roll, some will either almost win an item, or win an item. In how many different ways can this happen?
This makes four possible states for each raider: used bonus roll and won no item, used bonus roll and won item, used bonus roll and almost won an item, didn't use bonus roll.
Hopefully this rewrite will help you to understand how silly that seems.