Originally Posted by
heheMongot
f(x)=ax + b
f(ax+b)= a(ax+b)+b = a^2*x + ab + b
Since the only factor containing an x is (a^2*x) that must mean that the coefficient (a^2) must be equal to the coefficient of (x) which is then 1.
From here you see that the remaining factors (ab + b) need to make up the constant in the right side of your equation (1).
Either you just see from here that in order for (ab + b) to be 1 (b) needs to be (0,5) since (a=1) or you could solve it like this:
ab+b = 1
a=1
1b + b = 1
2b = 1
b = 1/2
This leaves us with a=1 and b=0,5
Hope this helps.